10^2+7^2=b^2

Solution for 10^2+7^2=b^2 equation:

10^2+7^2=b^2

We move all terms to the left:

10^2+7^2-(b^2)=0

We add all the numbers together, and all the variables

-1b^2+149=0

a = -1; b = 0; c = +149;
Δ = b2-4ac
Δ = 02-4·(-1)·149
Δ = 596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{596}=\sqrt{4*149}=\sqrt{4}*\sqrt{149}=2\sqrt{149}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{149}}{2*-1}=\frac{0-2\sqrt{149}}{-2}
=-\frac{2\sqrt{149}}{-2}
=-\frac{\sqrt{149}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{149}}{2*-1}=\frac{0+2\sqrt{149}}{-2}
=\frac{2\sqrt{149}}{-2}
=\frac{\sqrt{149}}{-1}
$